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検索キーワード「nonlinear association」に一致する投稿を表示しています

25 ++ Žè‘‚« ƒJƒbƒv ƒAƒCƒX ƒCƒ‰ƒXƒg 182153

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++ 50 ++ ƒyƒ“ƒP[ƒX ¬Šw¶ —‚ÌŽq ‚Šw”N 295242

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F ∀x ¬(∃y p(x,y) ∧ p(x,z)) ∨ ∃y p(x,y) ↑ to the end of the formula 1 Write F in NNF F1 ∀x (∀y ¬p(x,y) ∨ ¬p(x,z)) ∨ ∃y p(x,y) 2 21 2 Rename quantified variables to fresh names F2 ∀x (∀y ¬p(x,y) ∨ ¬p(x,z)) ∨ ∃w p(x,w) ↑ in the scope of ∀x 3# 6 r Ä ç « y/ KNN r Ä ç « 9 S Í ¢ 9 S Í ¢ y Æ « £ 9 S Í ¢ x L ä Ú E t l o s w p î M w ;Answer pq = log(xy) This is a Lagrange's equation whoes general formula is pPqQ=R This can be solved by the formula (dx/P)=(dy/Q)=(dz/R) Here, P=1 ,Q= 1 ,R=log(xy) Now, {dx/1}={dy/1}={dz/log(xy)} From the 1st two ratio, dx= dy => dxdy=0 Integrating above equation we get, xy Cmpe Boun Edu Tr ƒyƒ"ƒP[ƒX ¬Šw¶ —‚ÌŽq ‚Šw"N